# A 5-foot tall student stands 10 feet away from the lens of a camera. The film of the camera is 3 inches away from the lens. A 5 ft tall student is standing 10 feet away from the lens of a camera; behind the lens of the camera is shown the film of the camera, 3 inches away from the lens. What is the height of the film? Answer 0.2 inches 0.7 inches 1.2 inches 1.5 inches

Was there a picture included with this?

yes. one second

What exactly is the topic of study for your class?

meaning? Its geometry and that lesson was about similar triangles

That's what I needed to know

kk

Okay, I figured out what it was, but the explanation is kind of whacky

You're supposed to create a proportion relating the two triangles by setting height of the person to the height of the film equal to the length of the person from the lens to the length of the film from the lens.

right. I can get there but whats next?

do I cross multiply?

Next you cross multiply, then solve for x.

wait a second....

We need to convert feet to inches.

oh lord. I didnt notice that......

Yeah, I just realized it myself.

1/40 = 5/x ??

x = 200.........right?

So after converting ft to inches, you get 60 for the height of the person 120 the person's distance from the lens So replacing those in the proportion you get: \[\frac{60}{x}=\frac{120}{3}\]

Just kidding! geez my brain is fried

\[\frac{60}{x}=40\]

60 = 40x 6 = 4x 6/4 = x 2/3 = x

in inches, not feet

60/x = 40 x = 40/60 x = 4/6 x = 2/3 x = .67?

Yes

.7 inches. Yay!! thank you!

wait, lol

uh oh.......lol

I think I did that backwards

3/2 = x

60 = 40x 6 = 4x 6/4 = x 3/2 = x

1.5??

Yes

thanks!

Funny thing is, even if you don't convert, you still get 1.5 I find that very strange

ha

lol

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