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OpenStudy (anonymous):

Using trapezoid GHIJ, solve for x. 8 10 0 6

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OpenStudy (anonymous):

OpenStudy (netlopes1):

Use the relation EF = (GH+IJ)/2 or...

OpenStudy (netlopes1):

\[12=[(x+3)+(2x+3)]/2\rightarrow (x+3+2x+3)=24\rightarrow 3x+6=24\rightarrow 3x=18 \rightarrow x=6\] So, x = 6, ok?

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