Mathematics

OpenStudy (anonymous):
log₅(x-3)+log₅x=log₅4
how do i solve this?

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OpenStudy (shubhamsrg):
base is 5 ?

OpenStudy (anonymous):
yes

OpenStudy (anonymous):
u know the properties of logarithm, @mathnoob1 ?

OpenStudy (shubhamsrg):
well doesnt matter..
use this,,log a +log b = log ab
and if log m = log n
then m=n
try now
note : the bases should be equal here..

OpenStudy (anonymous):
if apply the properties, u will get x(x-3)=4
now, solve this

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OpenStudy (anonymous):
x²-3x=4 ???

OpenStudy (anonymous):
factor your equation

OpenStudy (anonymous):
roots will be 4 and -1
but u have to discard -1 as log of negative number is not defined
so, the answer will be 4

OpenStudy (anonymous):
hmm icic thank you everyone =)

OpenStudy (anonymous):
@ninhi5 , u r wrong

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OpenStudy (anonymous):
i see

OpenStudy (anonymous):
how do u define log(-2), @ninhi5 ?

OpenStudy (anonymous):
@Arnab09 is right.

OpenStudy (anonymous):
x.(x-3)=4

OpenStudy (anonymous):
well guy the answer for this is 4.. and aranb09 answer it right

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OpenStudy (anonymous):
x>0 and x-3>0

OpenStudy (anonymous):
checking doesn't matter

OpenStudy (anonymous):
so x=4

OpenStudy (anonymous):
guy this kind of equation can i actually use quadratic equation to solve it?

OpenStudy (anonymous):
haha it's late at night

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OpenStudy (anonymous):
gr8.. good night