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OpenStudy (anonymous):

Which of the following is the simplified form of (x^2-9)/(x-3) x - 3, with the restriction x ≠ 3 x + 3, with the restriction x ≠ 3 x - 3, with the restriction x ≠ -3 x + 3, with the restriction x ≠ -3 i can't figure it out i thought the answer was (a) please help

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OpenStudy (anonymous):

B because the numerator factored form is (x-3)(x+3)

Parth (parthkohli):

Let's just factor the numerator with the difference of squares formula. \(\Large \color{MidnightBlue}{\Rightarrow {(x + 3)\cancel{(x - 3)} \over \cancel{x - 3}} }\) \(\Large \color{MidnightBlue}{\Rightarrow (x + 3) }\)

Parth (parthkohli):

The restriction would be 3 as 3 - 3 = 0...and the denominator \(\ne\) 0.

OpenStudy (anonymous):

x cant be 3 because denominator cant be 0

OpenStudy (anonymous):

@ParthKohli you're fast

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Parth (parthkohli):

Bwahaa thanks

OpenStudy (anonymous):

thanks

OpenStudy (anonymous):

both of you are fast

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