Which of the following is the simplified form of (x^2-9)/(x-3)
x - 3, with the restriction x ≠ 3
x + 3, with the restriction x ≠ 3
x - 3, with the restriction x ≠ -3
x + 3, with the restriction x ≠ -3
i can't figure it out i thought the answer was (a)
please help

Question

Which of the following is the simplified form of (x^2-9)/(x-3)
x - 3, with the restriction x ≠ 3 
 x + 3, with the restriction x ≠ 3 
 x - 3, with the restriction x ≠ -3 
 x + 3, with the restriction x ≠ -3 
i can't figure it out i thought the answer was (a)
please help

anonymous · Answer

B because the numerator factored form is (x-3)(x+3)

parthkohli · Answer

Let's just factor the numerator with the difference of squares formula.

$\Large \color{MidnightBlue}{\Rightarrow {(x + 3)\cancel{(x - 3)} \over \cancel{x - 3}} }$

$\Large \color{MidnightBlue}{\Rightarrow (x + 3) }$

parthkohli · Answer

The restriction would be 3 as 3 - 3 = 0...and the denominator $\ne$ 0.

anonymous · Answer

x cant be 3 because denominator cant be 0

anonymous · Answer

@ParthKohli you're fast

parthkohli · Answer

Bwahaa thanks

anonymous · Answer

thanks

anonymous · Answer

both of you are fast