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Mathematics
Which of the following is the simplified form of (x^2-9)/(x-3) x - 3, with the restriction x ≠ 3 x + 3, with the restriction x ≠ 3 x - 3, with the restriction x ≠ -3 x + 3, with the restriction x ≠ -3 i can't figure it out i thought the answer was (a) please help
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B because the numerator factored form is (x-3)(x+3)
Let's just factor the numerator with the difference of squares formula. \(\Large \color{MidnightBlue}{\Rightarrow {(x + 3)\cancel{(x - 3)} \over \cancel{x - 3}} }\) \(\Large \color{MidnightBlue}{\Rightarrow (x + 3) }\)
The restriction would be 3 as 3 - 3 = 0...and the denominator \(\ne\) 0.
x cant be 3 because denominator cant be 0
@ParthKohli you're fast
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Bwahaa thanks
thanks
both of you are fast
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