Question

Algebra Mixture:
How many liters of 7% acid must be mixed with how many liters of 12% acid solution by a chemist to obtain 6 liters of 10% acid?

Answer 1

Ok so i think this is how you write it but im putting this up to make sure.
So first you write .07x+12(6-x)=(6)(0.1) then, when you solve it you get x=2.4

Answer 2

Anybody know if its right and want to tell me?

Answer 3

ok, this isn't a mixture...

Answer 4

It si , it says mixtures on the top of the page... lol

Answer 5

but whatever you may call it, if you know the answer please help i have like 40 more topics to study and my exam is in 2 days

Answer 6

Here is how I would think about it. 6 liters of 10% acid is .6 liters of acid in 6 liters total. You have two other solutions your mixing, and you want \(x+y=6\), \(.07x+.12y=.6\). You're solving for \(x\), so put the first equation in terms of \(y\), \(y=6-x\), then substitute: \(.07x+.12(6-x)=.6\). So yeah, that was a long way of saying that your equation was correct.

Answer 7

oh lol tysm :) you really helped xD

Answer 8

Let x = amount of 7% solution to add
Then 6-x = amount of 12 % solution to add
.07x+.12(6-x)=.10(6)

Answer 9

Ok...the long, roundabout way. lol

Answer 10

And yes. You did it right.

Answer 11

Thanks :)

Answer 12

yw

Answer 13

I like mertsj answer better, sorry nbouscal

Answer 14

Both are good and help me alot, thanks to all three of you, ill remember you guys when i take my exam xD lol

Answer 15

you can just become fans. ☺

Answer 16

lol i thought i already was for all 3

Answer 17

I always used to teach my students to write the first equation based on the amount of solution:
x+(6-x)=6
A very trivial but useful equation.
Not based on that, put in the percents and write the equation based on the amount of solute:
.07x+.12(6-x)=.10(6)

Answer 18

Now based on that, I meant to say.

Answer 19

Looks like we have a math teacher lol

Answer 20

xD