Question

sqrt(-64) /(7-6i)-(2-2i)

Answer 1

anyone know this?

Answer 2

yes here i come
sqrt-64=8i
The denominator is (7-6i)-(2-2i)?

Answer 3

how do i distribute the denominator?

Answer 4

multiply to it's conjugate

Answer 5

so the conjugate of both ?

Answer 6

multiply to (conjugate of denominator)/(conjugate of denominator)
Is this clear?

Answer 7

would it be 14+12i ?

Answer 8

Did u mean the conjugate?

Answer 9

after i multiplied both by the conjugate would i get that?

Answer 10

yes no?

Answer 11

I think no.

Answer 12

i don't understand this prob. at all

Answer 13

is sqrt -64 divide by (7-6i)-(2-2i) OR
divide (7-6i) then whole thing minus (2-2i)?

Answer 14

im sorry i still do not understand it

Answer 15

\[\frac{\sqrt {-64}}{(7-6i)-(2-2i)}\]
or
\[\frac{\sqrt{-64}}{7-6i}-(2-2i)\]
which one?

Answer 16

the second one

Answer 17

ok
sqrt -64=8i
8i(7+6i)=56i-48--->(Note that i x i=-1)
(7-6i)(7+6i)=49+36=85--->Using(a+b)(a-b)=a^2-b^2(also note that i^2=-1)
so it is
\[\frac{-48+56i}{85}\]

Answer 18

after that u can do normal subtraction

Answer 19

how?