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For fun, Solve DE
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\[(e^y+1)^2e^{-y}dx+(e^x+1)^3e^{-x}dy=0\]
I do believe the book did something crazy with simplifying so we might all have different answers
that wouldn't be fun @binary3i
yeah.
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besides, wolfram sucks at DE's anyway here's an example I keep to remind myself of that http://www.wolframalpha.com/input/?i=4y%27%27%2B8y%27%2B2y%3Dcos%5E2x
(e^y-1) +2(e^x+1)^2=C
really doesn't look that bad to me \[\frac{(e^y)+1)^3}{e^y}dx+\frac{(e^x+1)^3}{e^x}dy=0\]
\[\frac{(e^y+1)^2}{e^y}dx=-\frac{(e^x+1)^3}{e^x}dy\]
cf = \[\frac{e^ye^x}{((e^y+1)^2)((e^x+1)^3)}\]
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\[\frac{e^x}{(e^x+1)^3}dx=-\frac{e^y}{(e^y+1)^2}dy\]
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