Help?? (Don't ditch me like other have done) A liquid filter shaped as a right circular cone is shown below. If a similar cone has a slant height of 24 cm, what is its lateral area?
Lets us find the height first. Do you know how?
why do we need the height we already have the slant height?
In similar cones the height and radius are in proportion.
then I guess I would not know the height..
Use Pythagorean Theorem.
the height would be 22?
No.
no dimmy... use the pythagorean theorem on this... solvefor h... |dw:1338224704106:dw|
5^2+20^2=h correct?
No.
then idk..
you said use pythgoran theorem? Which is a^2+b^2=c^2 ??
20 is the hypotenuse... so c=20. solve for h. it is one of a or b in a^2+b^2=c^2
so it's 15
ok so i have figured out the height, now what?
........
I think \[S = \pi*r*l\] S -area \[\pi=3,14\] r-radius = 5 l- height = 20cm S = 3,14 * 5*20 =314 But I don't sure
i got that too. But that is not one of the choices. The other two guys that were helping me ditched me (ofcourse).
its Pie times r times 24 + pie times r squared
well here are the answers: 72π cm2 120π cm2 144π cm2 256π cm2 And i didn't get a match :/
Okay. The lateral area of a cone is given by\[A_L=\pi r L\] where r is the radius of the cone and L is the slant height. Do you have the radius and slant height of the larger cone?
Hello? @DimDanny?
@Palmo4ka, for the smaller cone it is 5, but @DimDanny needs to determine the lateral area of the larger cone.
To determine the radius of the larger cone, we know that the cones are similar so therefor, the ratio of the slant heights equal the ratio of the radii \[\frac{20}{24}=\frac{5}{r}\]where r is the radius of the larger cone.
Hence, r the large cone = 6
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