Question

Write the given equation in standard form and determine the center and radius.
x2 + 4x + y2 – 10y – 35 = 0

Answer 1

you'll need to complete the square to get it into the standard form:
(x-h)^2 + (y-k)^2 = r^2
to find the center (h,k) and radius r.

complete the square on:
x^2 + 4x + y^2 – 10y – 35 = 0
(x^2 + 4x ) + (y^2 – 10y ) =35

what do you need to add to each of those parenthesis to make each a perfect square trinomial?

Answer 2

idk what?

Answer 3

take half of the linear coefficient and square it. that is what you need to add to each to make each parenthesis into a perfect square trinomial.

what's the coefficient of the linear term (x), in the first parenthesis?

Answer 4

2

Answer 5

no. the coefficient of the linear term is 4...
take half of that, then square it: 4/2=2 ---> 2^2=4
this is what you need to add to the first parenthesis.
(x^2 + 4x + 4) + (y^2 – 10y ) =35

can you find out what you need to add to make that second parenthesis a perfect square trinomial....

Answer 6

4?

Answer 7

(x^2 + 4x + 4) + (y^2 – 10y ) =35 + 4
(x^2 + 4x + 4) + (y^2 – 10y + 25 ) =35 + 4 + 25
(x+2)^2 + (y-5)^2 = 64

ok.. i completed it for you. you need to determine the center and radius from here. that last equation contains everything you need to know about the center and radius...:)