Solve the equation 2cos(x) - 1 = 0 Possible answers: A. x = (π/6) + 2nπ and x = (5π/6) + 2nπ, where n is an integer. B. x = (π/3) + 2nπ and x = (5π/3) + 2nπ, where n is an integer. C. x = (π/4) + 2nπ and x = (5π/4) + 2nπ, where n is an integer. D. x = (π/6) + 2nπ and x = (7π/6) + 2nπ, where n is an integer. E. x = (2π/3) + 2nπ and x = (4π/3) + 2nπ, where n is an integer.
in the equation add 1 to both sides then divide by 2 to get this equation: cos(x) = 1/2 now think of an angle such that when you take the cosine of that angle you get 1/2....
I'm not quite sure what you mean
Can you explain further or clarify?
do you have your unit circle?
yes
look at the common angles and see which angle gives a cosine of 1/2...
what coordinate does cosine refer to... the x coordinate or y coordinate?
I'm not sure. I don't have much practice with unit circles
look at page 3 here.... and tell me what angle corresponds to the x coordinate being 1/2... http://tutorial.math.lamar.edu/pdf/Trig_Cheat_Sheet.pdf
K. Give me a second... my internet is slow.
It looks like both 300 degrees and 60 degrees have an x coordinate of 1/2
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