Question

for what value of t is (t+1, 2,t) orthogonal to (1,1,1)? can anyone help please

Answer 1

when t.v = 0

Answer 2

thanks

Answer 3

do you know how to do a dot product?

Answer 4

yes i just dont understand the question some english is second language

Answer 5

then you should be good to go ;)

Answer 6

so i got vatue of t=3/1 that mean not orthogonat am i right

Answer 7

(t+1, 2,t) dot (1,1,1) = (t+1)+(2)+(t)

t+1+2+t = 0 , and solve for t

Answer 8

yes i got t=3/2

Answer 9

then when t=3/2, the vectors are orthogonal

Answer 10

i think its a -3/2 tho

Answer 11

thant is right

Answer 12

any idea about this \[give the parametric equestion for the following line.a) the line through (2,9,0) and (-1,5,1)\]

Answer 13

try not to type text in latex

Answer 14

ok

Answer 15

a parametric is defined as the point attached to the scaled vector parts

Answer 16

given a point (x,y,z), and a vector <a,b,c>

the parametric is defined as:

x = x + at
y = y + bt
z = z + ct

Answer 17

but i dont have vector here do i have to use dot product to find v

Answer 18

i cant read what the information is, can you retype it?

Answer 19

i dont have the vatue of the vector do have to use dot product to find vector

Answer 20

are you given 2 points that need to be on the line?

Answer 21

given point A and point B

the vector between them is simply: A-B