Question

write the equastion
the plane through (1,0,0) which is parallel to both of the line r(t)=2t,3t,1-t) and s(t)=(t,1,1-t) can help me with this please

Answer 1

This is the form of Point- normal plane:
From the both lines parallel to the plane, using cross product:
-> normal vector n = < -3, 1, -3 >
and Point ( 1, 0, 0 )
=> Point- Normal plane: -3 ( x - 1) + y - 3 z = 0
Thus Plane equation: -3x + y - 3z + 3 = 0

Answer 2

@linda1 Any comment ?

Answer 3

it is right but is -3x+y-3z=-3

Answer 4

but thank u very muck

Answer 5

calcus 3

Answer 6

Just leave the message if you need more help!

Answer 7

sure thx

Answer 8

how can solve this
the plane through the orginwith is perpendicular to both
of plane x-y+z=2 and x+y+z=1

Answer 9

Would you open the new post for this question, pls!

Answer 10

sure