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Based on Descartes' Rule, the maximum number of positive real zeros f(x) = 4x4 - 13x3 + 25x2 - 54x + 81, could have is help me please!
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4, 2, or 0 because you see how many times the coefficient changes signs when going in descending order.
\[f(x) =4x^4 - 13x^3 + 25x^2 - 54x + 81\] There are 4 change of sign, hence 4.
4 would be the maximum though
thanks!!
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