Question

In how many ways can a teacher arrange 10 students in the front row if there are 25 total students? this is a combination not a permutation right?

Answer 1

I would think of this as a permutation. Mainly because order matters in how students are seated since each student is different.

Answer 2

\[10! \times \binom{25}{10} =11861676288000 \]

Answer 3

Tip: "arrangement" is always permutation.

Answer 4

Or just \[25P10=\frac{25!}{(25-10)!}\]

Answer 5

Thanks guys sorry I'm exhausted and need to finish 2 more assignments and my head can't process