Question

what does this mean...

obtain the particular solution satisfying the initial condition indicated

\[xy^2 dx + e^xdy = 0\] when \(x \rightarrow \infty\), \(y \rightarrow 1\)

Answer 1

we see that
dy/dx = (-xy^2)/e^x
=> dy/ y^2 = -xe^-x dx
just integrate both sides
use this on RHS
integral (uv) = u*integral(v) - integral[u' * integral(v)]
will this help?

Answer 2

so it's by parts?

Answer 3

the very same i'd guess..

Answer 4

hmm..ok then...