Question

Help!!!

Answer 1

From the given information,
triangle DHF ~ triangle CGA
\(\frac{3}{7} = \frac{x+3}{3x-2}\) ( corr. sides, ~triangles)
Solve the equation ~

Answer 2

What do I put in place of x?

Answer 3

@Callisto

Answer 4

Sorry, what do you mean?

Answer 5

I'm not sure how to solve it.

Answer 6

Cross multiplication
\[\frac{3}{7} = \frac{x+3}{3x-2}\]
3(3x-2) = 7(x+3)
Can you solve it?

Answer 7

3x + 9
21x - 14

Answer 8

@lgbasallote Can I get some help?

Answer 9

First expand the terms on both sides
3(3x-2) = 7(x+3)
3(3x) - 3(2) = 7(x) + 7(3)
9x - 6 = 7x +21

Then, solve the equation:
1. add 6 to both sides
2. subtract 7x from both sides
3. divide both sides by the coefficient of x
Can you try and show your work?

Answer 10

Woops, I messed up on one number up there ^

Answer 11

2x = 21

Answer 12

10.5

Answer 13

Nope :|
9x - 6 = 7x +21
1. add 6 to both sides -> what do you get?

Answer 14

9x - 6 = 7x + 21
+6 +6
27

9x = 7x + 21
-7x =-7x

2x = 21

Answer 15

Well... you've +6 on the right to get 27, why did you write 21?

Answer 16

7 x 3 = 21

Answer 17

wait. 21 + 6 = 27

Answer 18

Can you show it clearly?
What do you get when you add 6 to both sides of the equation 9x - 6 = 7x +21?

Answer 19

9x = 7x + 27

Answer 20

I see where I messed up.

Answer 21

2x = 27

Answer 22

Now, you'be got 2x = 27
3. divide both sides by the coefficient of x -> what do you get?

Answer 23

So the answer would be 13.5 Got it! Thanks!!!

Answer 24

Welcome :)

Answer 25

Guessing you do this the same way. Could you help me set it up?

Answer 26

@Callisto

Answer 27

Similar... Can you try the set the equation using property of similar triangle?
(corr. sides, ~ triangles)

Answer 28

13 (x + 9)
8 (2x + 5)

Answer 29

It's an equation... at least you should have an equal sign?
Hint:
\[\frac{x_1}{y_1}=\frac{x_2}{y_2}\]
x1, x2 are the sides of 1st triangle
y1, y2 are the sides of 2nd triangle

Answer 30

8 (x+9)
_ =

13 (2x + 5)

Answer 31

Yup!~
next: cross multiplication

Answer 32

so what i previously had? just in fraction form?