Question

in trigonal pyramidal on equatorial there s,Px,Py orbital are used and on axial Pz , dz^2 are used. i m not gettin how we come to knw that which orbital is used?

Answer 1

now explain me :)

Answer 2

hehe i found a part of it but its in my language (croatian) so i cant just take picture and attach it... one minute so i look a bit further

Answer 3

ok and for example uca explain me by PCl5

Answer 4

PCl5, phosphorus config is 1s2 2s2 2p6 3s2 3p3
so I think the phosphorus is hybridized in sp3d

Because phosphorus is in period 3 and it can expand octet due to the presence of 3d orbitals, the electrons can be filled in the d orbitals so no need to observe the 8 full electron rule.

Answer 5

oh how easy would it be if i could just take a photo of this, but ill attach photos of diagrams

Answer 6

take ur own time @Kryten and yea @sam as i mention i m not gettin how we come to knw which orbital of d is used ..

Answer 7

here is the gallery:
https://www.dropbox.com/gallery/18262700/1/Heena?h=7ed60b

Answer 8

It really helps to see how the orbitals are arranged in three-dimensional space. Take a look at the picture I attached for s, p, and d orbital shapes.

There are five bonds in trigonal pyramidal so the hybridization is sp3d (s + p + p + p + d). Meaning, there will be one s, three p, and one d orbital involved. Based on how the x,y,z axes are traditionally setup, x goes to the left and right, y goes forward and back, and z goes up and down. From that perspective, you should see that the three equatorial bonds are in the xy-plane, so you use s(?), p_x, and p_y. Two other bonds remain, those are both on the z-axis, so the last remaining p orbital (p_z) makes sense, and add a d-orbital that has z-character: d_z2 is the best choice.

I hope that helps.

Answer 9

thank you guys :)