A grain silo is shown below.
What is the volume of grain that could completely fill this silo rounded to the nearest whole number? Use 22/7 for pi.
13,750 ft3
14,012 ft3
262 ft3
4,583 ft3
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OpenStudy (anonymous):
OpenStudy (anonymous):
You can find two volumes:
The cylinder
The Hemisphere
OpenStudy (anonymous):
How would I?
OpenStudy (anonymous):
Well the volume of the cylinder is the base times the height. The base in this case is a circle with an area of
\[\pi r^2\]
where r=5
OpenStudy (anonymous):
so the area is
\[25 \pi\]
Times the height which is given. Can you tell me the height?
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OpenStudy (anonymous):
So that would be 78.5 times 175?
OpenStudy (anonymous):
correct thats the volume of the cylinder
OpenStudy (anonymous):
Now for the hemisphere.
OpenStudy (anonymous):
\[\frac{2}{3} \pi r^3\]
OpenStudy (anonymous):
well you could directly use phi r^2(2/3r+h) where r stands for radius and h stands for height
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OpenStudy (anonymous):
that's the formula for it. Plug in the radius and you have the volume of the hemisphere. Add that to the volume of cylinder and you are done.
OpenStudy (anonymous):
Well that's basically what I did.
OpenStudy (anonymous):
so 22/7 (5)^2 (2/3 (5) + 175) is that it?
OpenStudy (anonymous):
yes!
OpenStudy (anonymous):
14011.9?
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