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Mathematics 15 Online
OpenStudy (anonymous):

A grain silo is shown below. What is the volume of grain that could completely fill this silo rounded to the nearest whole number? Use 22/7 for pi. 13,750 ft3 14,012 ft3 262 ft3 4,583 ft3

OpenStudy (anonymous):

OpenStudy (anonymous):

You can find two volumes: The cylinder The Hemisphere

OpenStudy (anonymous):

How would I?

OpenStudy (anonymous):

Well the volume of the cylinder is the base times the height. The base in this case is a circle with an area of \[\pi r^2\] where r=5

OpenStudy (anonymous):

so the area is \[25 \pi\] Times the height which is given. Can you tell me the height?

OpenStudy (anonymous):

So that would be 78.5 times 175?

OpenStudy (anonymous):

correct thats the volume of the cylinder

OpenStudy (anonymous):

Now for the hemisphere.

OpenStudy (anonymous):

\[\frac{2}{3} \pi r^3\]

OpenStudy (anonymous):

well you could directly use phi r^2(2/3r+h) where r stands for radius and h stands for height

OpenStudy (anonymous):

that's the formula for it. Plug in the radius and you have the volume of the hemisphere. Add that to the volume of cylinder and you are done.

OpenStudy (anonymous):

Well that's basically what I did.

OpenStudy (anonymous):

so 22/7 (5)^2 (2/3 (5) + 175) is that it?

OpenStudy (anonymous):

yes!

OpenStudy (anonymous):

14011.9?

OpenStudy (anonymous):

ya may be !

OpenStudy (anonymous):

Thats not an answer choice

OpenStudy (anonymous):

well that's it . it's 14012

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