Question

the average of x, y and z is one-third greater than x. the sum y+z is what percent greater than x?

Answer 1

\(\Large \color{Black}{\Rightarrow {x + y + z \over 3} = {1 \over 3} + x }\)

\(\Large \color{Black}{\Rightarrow 3x + 1 = x + y + z }\)

\(\Large \color{Black}{\Rightarrow 2x + 1 = y + z }\)

Hmm

Answer 2

I think you meant \[{x + y + z \over 3} =(1+{1 \over 3}) x \]

Answer 3

the sum y+z is what percent greater than x?

Answer 4

???? Percent???

Answer 5

Till here I figured out?!!! I cudn't figure out what percent????

Answer 6

Just a sec - confirming - Is Parth's version the right one or is pfenn's? #"one third greater than x"

Answer 7

Simplify the equation I gave you and then rearrange so that you have y+z on the left side of the equation and see what you come out with.

Answer 8

@pfenn1 Simplified and i got y+z = 3x that means the sum of y and z is equal to 3 times x or 300% of x. Am i right?

Answer 9

Correct!

Answer 10

One thing I can't figure out: When it's written greater than do we have to add?

Answer 11

?

Answer 12

Mostly, but it really depends on the wording. The problem that @ParthKohli had was that he wasn't multiplying x by the fraction and that you have to add the fraction to 1 because the average was 1/3 great than x. If you just multiply by 1/3, you will get an answer that is 1/3 of x but you really want 1/3 more than x. So you have to multiply by 1+(1/3).

Answer 13

that means the sum is one third of x greater than x?

Answer 14

So that can be said as 4/3x right?

Answer 15

@pfenn1 please reply @ParthKohli yeah

Answer 16

Then do it :P

Answer 17

did it told the answer already above.

Answer 18

Hi. Sorry, I had an appointment. Yes, Zeerak