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Find the 5th term of the sequence in which t1 = 8 and tn = -3tn-1.
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8 = 3n - 1 9 = 3n n = 3\[\sum_{3}^{7} (3n - 1)\] \[a _{5} = 3n - 1 = 21 - 1 = 20\]
I have one question left: Find the 6th term of the sequence with t1 = -4 and tn = 5tn-1.
I'm not very sure with this one...sorry.
oh im sorry i meant this Find the 6th term of the sequence with t1 = -4 and tn = 5^tn-1
the last one is squared
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So, \[t _{n} = 5^{n - 1}?\]
yea
I think you should ask someoone else because this involves logs and I'm not good at them.
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