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Mathematics 15 Online
OpenStudy (anonymous):

(x^2 + 6x + 9) / (5x + 15)

OpenStudy (anonymous):

(x+3)/5

OpenStudy (anonymous):

how did you get that:?

Parth (parthkohli):

I see that x^2 + 6x + 9 is a perfect square of x + 3. In other words, we can factor \(x^2 + 6x + 9 \) as \((x+3)^2\) 5x + 15 has a common factor of 5, so it's factored as 5(x + 3) Hint: Something gets cancelled now :D

OpenStudy (anonymous):

x + 3?

Parth (parthkohli):

yes, x + 3 gets cancelled. What are you left with?

OpenStudy (anonymous):

x2 + 6x + 9 / 5?

Parth (parthkohli):

Obviously, you are left with: \(\Large \color{Black}{\Rightarrow {(x + 3)\cancel{(x + 3)} \over 5\cancel{(x + 3)}} }\) \(\Large \color{Black}{\Rightarrow {x + 3 \over 5} }\)

OpenStudy (anonymous):

right sorry I had a terible connction

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