Which rule represents the translation of hexagon DEFGHI to hexagon D'E'F'G'H'I'? (x, y)→(x + 4, x – 2) (x, y)→(x – 7, y + 7) (x, y)→(x + 2, x – 4) (x, y)→(x + 7, y – 7)
Pick a letter, any letter (of this list)
ohh okay brb sorry
sorry about that, I got distracted for a second
let me know when you want to start
k im back but i think it is the last one because u add 7 to y which will take u to the right and then downward 7 for y
you nailed it, so the answer is...?
oh nvm, you already said it's the last one
so choice D is your answer
(x, y)→(x + 7, y – 7)
you got it, very nice work
thank u :)
you're welcome
here is the next one : Which two transformations are applied to pentagon ABCDE to create A'B'C'D'E'? translated according to the rule (x, y) → (x + 7, y + 1) and reflected across the x-axis translated according to the rule (x, y) → (x + 1, y + 7) and reflected across the axis translated according to the rule (x, y) → (x + 7, y + 1) and reflected across the y-axis translated according to the rule (x, y) → (x + 1, y + 7) and reflected across the y-axis
if we move the figure over to the right 7 units, we're adding 7 to each x value. This will place the figure directly underneath the new figure
So x --> x+7
Now notice how the point A' is 1 unit away from the x axis. So we need to move A so that it is 1 unit away from the x axis as well (so we can do a proper reflection)
so this means we need to move the points up one unit, so y --> y+1
since x --> x+7 and y --> y+1, the transformation is (x,y) --> (x+7, y+1), with me so far?
ya writing it down lol thank u
Alright, just wanted to be sure So we have (x,y) --> (x+7, y+1) This will translate the original figure directly underneath the new figure. To complete the transformation, we then follow with a reflection over the x axis So the answer is choice A
ohh okay it the same thing just in a different location and ur trying to figure out the coordinates makes since
If quadrilateral L'M'N'O' represents the reflection of quadrilateral LMNO across the line y = x, which point is at the ordered pair (-1, 1)? N' O' L' M'
To reflect any point (x,y) across the line y = x, all you do is swap the x and y coordinates So (x,y) ---> (y,x) So we know (x,y) ---> (-1, 1), what is the value of (x,y)?
i have no idea to be honest with u
probably the strange notation that's getting you...notice point N (1, -1) Use the rule (x,y) ---> (y,x) to get N ---> N' (1,-1) ---> (-1,1) So N' is at the point (-1,1) You can find this by trial and error or by going backwards from the answer (then going forwards)
okay so the answer would be n im sorry im trying to figure it out :/
no it's N', so you are close
oh I think that's what you meant
lol ya thats what i meant i just did it lower case lol
i gotcha lol
If trapezoid JKLM is translated according to the rule (x, y) → (x + 8, y - 3), what are the coordinates of point L'? (1, -5) (-10, 6) (-5, 3) (6, -8)
What is point L
Ie what are the coordinates of point L
-2, -5
Good, so (x,y) ---> (x+8, y-3) tells us to add 8 to the x coordinate and subtract 3 from the y coordinate
okay so it would then be 6, -8
you got it
i do??
yes, the answer is choice D
cool thank u If triangle XYZ is reflected across the line y = 1 to create triangle X'Y'Z', what is the ordered pair of X'? (1, -5) (1, -3) (1, 3) (1, 5)
The y coordinate of X is y = -3 The distance y = 1 is from y = -3 is |-3-1| = 4 units So we need to add 4 units to y = 1 to get y = 1+4 = 5 This means that X' is at the point (1,5)
hmm now that I look at it, it might be a bit confusing (with the notation). Let me know what you think.
i get that
alright great
thank u so much u r a great help seriously u dont even know i wish u were my teacher
If trapezoid T'U'V'W' represents trapezoid TUVW reflected over the y-axis, the ordered pair of W' is
To reflect ANY point over the y axis, you simply change the sign of the x coordinate So (x,y) ---> (-x,y) Ex: (1,2) reflects over the y axis to (-1,2) Note: the answer isn't (-1,2), this is just an example
okay lol
so what did you get for the answer?
-3,222
-3,2
well W is (2,3), so W' should be (-2,3)
You only change the sign of the x coordinate when you reflect over the y axis
oh okay i understand
that's great :)
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