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Mathematics 23 Online
OpenStudy (anonymous):

Which rule represents the translation of hexagon DEFGHI to hexagon D'E'F'G'H'I'? (x, y)→(x + 4, x – 2) (x, y)→(x – 7, y + 7) (x, y)→(x + 2, x – 4) (x, y)→(x + 7, y – 7)

OpenStudy (anonymous):

jimthompson5910 (jim_thompson5910):

Pick a letter, any letter (of this list)

OpenStudy (anonymous):

ohh okay brb sorry

jimthompson5910 (jim_thompson5910):

sorry about that, I got distracted for a second

jimthompson5910 (jim_thompson5910):

let me know when you want to start

OpenStudy (anonymous):

k im back but i think it is the last one because u add 7 to y which will take u to the right and then downward 7 for y

jimthompson5910 (jim_thompson5910):

you nailed it, so the answer is...?

jimthompson5910 (jim_thompson5910):

oh nvm, you already said it's the last one

jimthompson5910 (jim_thompson5910):

so choice D is your answer

OpenStudy (anonymous):

(x, y)→(x + 7, y – 7)

jimthompson5910 (jim_thompson5910):

you got it, very nice work

OpenStudy (anonymous):

thank u :)

jimthompson5910 (jim_thompson5910):

you're welcome

OpenStudy (anonymous):

here is the next one : Which two transformations are applied to pentagon ABCDE to create A'B'C'D'E'? translated according to the rule (x, y) → (x + 7, y + 1) and reflected across the x-axis translated according to the rule (x, y) → (x + 1, y + 7) and reflected across the axis translated according to the rule (x, y) → (x + 7, y + 1) and reflected across the y-axis translated according to the rule (x, y) → (x + 1, y + 7) and reflected across the y-axis

jimthompson5910 (jim_thompson5910):

if we move the figure over to the right 7 units, we're adding 7 to each x value. This will place the figure directly underneath the new figure

jimthompson5910 (jim_thompson5910):

So x --> x+7

jimthompson5910 (jim_thompson5910):

Now notice how the point A' is 1 unit away from the x axis. So we need to move A so that it is 1 unit away from the x axis as well (so we can do a proper reflection)

jimthompson5910 (jim_thompson5910):

so this means we need to move the points up one unit, so y --> y+1

jimthompson5910 (jim_thompson5910):

since x --> x+7 and y --> y+1, the transformation is (x,y) --> (x+7, y+1), with me so far?

OpenStudy (anonymous):

ya writing it down lol thank u

jimthompson5910 (jim_thompson5910):

Alright, just wanted to be sure So we have (x,y) --> (x+7, y+1) This will translate the original figure directly underneath the new figure. To complete the transformation, we then follow with a reflection over the x axis So the answer is choice A

OpenStudy (anonymous):

ohh okay it the same thing just in a different location and ur trying to figure out the coordinates makes since

OpenStudy (anonymous):

If quadrilateral L'M'N'O' represents the reflection of quadrilateral LMNO across the line y = x, which point is at the ordered pair (-1, 1)? N' O' L' M'

jimthompson5910 (jim_thompson5910):

To reflect any point (x,y) across the line y = x, all you do is swap the x and y coordinates So (x,y) ---> (y,x) So we know (x,y) ---> (-1, 1), what is the value of (x,y)?

OpenStudy (anonymous):

i have no idea to be honest with u

jimthompson5910 (jim_thompson5910):

probably the strange notation that's getting you...notice point N (1, -1) Use the rule (x,y) ---> (y,x) to get N ---> N' (1,-1) ---> (-1,1) So N' is at the point (-1,1) You can find this by trial and error or by going backwards from the answer (then going forwards)

OpenStudy (anonymous):

okay so the answer would be n im sorry im trying to figure it out :/

jimthompson5910 (jim_thompson5910):

no it's N', so you are close

jimthompson5910 (jim_thompson5910):

oh I think that's what you meant

OpenStudy (anonymous):

lol ya thats what i meant i just did it lower case lol

jimthompson5910 (jim_thompson5910):

i gotcha lol

OpenStudy (anonymous):

If trapezoid JKLM is translated according to the rule (x, y) → (x + 8, y - 3), what are the coordinates of point L'? (1, -5) (-10, 6) (-5, 3) (6, -8)

jimthompson5910 (jim_thompson5910):

What is point L

jimthompson5910 (jim_thompson5910):

Ie what are the coordinates of point L

OpenStudy (anonymous):

-2, -5

jimthompson5910 (jim_thompson5910):

Good, so (x,y) ---> (x+8, y-3) tells us to add 8 to the x coordinate and subtract 3 from the y coordinate

OpenStudy (anonymous):

okay so it would then be 6, -8

jimthompson5910 (jim_thompson5910):

you got it

OpenStudy (anonymous):

i do??

jimthompson5910 (jim_thompson5910):

yes, the answer is choice D

OpenStudy (anonymous):

cool thank u If triangle XYZ is reflected across the line y = 1 to create triangle X'Y'Z', what is the ordered pair of X'? (1, -5) (1, -3) (1, 3) (1, 5)

jimthompson5910 (jim_thompson5910):

The y coordinate of X is y = -3 The distance y = 1 is from y = -3 is |-3-1| = 4 units So we need to add 4 units to y = 1 to get y = 1+4 = 5 This means that X' is at the point (1,5)

jimthompson5910 (jim_thompson5910):

hmm now that I look at it, it might be a bit confusing (with the notation). Let me know what you think.

OpenStudy (anonymous):

i get that

jimthompson5910 (jim_thompson5910):

alright great

OpenStudy (anonymous):

thank u so much u r a great help seriously u dont even know i wish u were my teacher

OpenStudy (anonymous):

If trapezoid T'U'V'W' represents trapezoid TUVW reflected over the y-axis, the ordered pair of W' is

jimthompson5910 (jim_thompson5910):

To reflect ANY point over the y axis, you simply change the sign of the x coordinate So (x,y) ---> (-x,y) Ex: (1,2) reflects over the y axis to (-1,2) Note: the answer isn't (-1,2), this is just an example

OpenStudy (anonymous):

okay lol

jimthompson5910 (jim_thompson5910):

so what did you get for the answer?

OpenStudy (anonymous):

-3,222

OpenStudy (anonymous):

-3,2

jimthompson5910 (jim_thompson5910):

well W is (2,3), so W' should be (-2,3)

jimthompson5910 (jim_thompson5910):

You only change the sign of the x coordinate when you reflect over the y axis

OpenStudy (anonymous):

oh okay i understand

jimthompson5910 (jim_thompson5910):

that's great :)

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