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Mathematics 20 Online
OpenStudy (anonymous):

Can someone help me here, please? Consider a triangle ABC. Given the vertex A=(4,1), the AB midpoint M=(2, -1) and the barycentre G=(-2,0), find the vertexes B and C. Well, through a graph I managed to find B=(0,-3). Then I thought about using the formula Barycentre(X)=(X(a) + X(b) + X(c))/3 Which would be like -2 = (4 + 0 + X(c))/3 and X(c)=-10, but my book says C=(-4, 1/2). Where did I go wrong?

OpenStudy (kinggeorge):

Could you give me a quick explanation of what the barycentre is?

OpenStudy (anonymous):

the gravity point of a triangle

OpenStudy (anonymous):

http://www.brasilescola.com/upload/e/baricentro.JPG

OpenStudy (kinggeorge):

So then informally, your barycentre should be the average value of your triangle

OpenStudy (anonymous):

What do you mean?

OpenStudy (kinggeorge):

I mean that your formula makes sense in an informal way, so I believe that it's correct. I'm also getting -10 for the x-value of C. In fact, if you graph it, an x-value of -4 makes very little sense.

OpenStudy (kinggeorge):

They seem to entirely discounting the point A for their calculation of the x-coordinate. What are you getting for the y-coordinate?

OpenStudy (anonymous):

I'm getting y = 2

OpenStudy (kinggeorge):

Same here.

OpenStudy (anonymous):

My book must be wrong then

OpenStudy (anonymous):

Thanks

OpenStudy (kinggeorge):

You're welcome.

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