Question

B = 703 * w/h (squared) Note: w/h is a fraction where h is squared

Part A: Solve for W

Answer 1

okay, so the whole thing is divided by h^2

Answer 2

\[B=\frac{W}{h^2}\]
Multiply both sides by h^2
\[Bh^2=W\]
Substitute B and h into equation
\[W=(21.45)(64)^2\]
Solve

Answer 3

Thank you Sam for helping me with Part B. I still need help with Part A which is:
\[B = 703 * \left(\begin{matrix}w \\ h ^{2}\end{matrix}\right)\] , solve for W

Answer 4

Part A
B = 703 * w/h
multiply both sides by h
Bh=703w
divide both sides by 703
\[w=\frac{Bh}{703}\]

Answer 5

the h is squared though. So, I would divide both sides by h squared instead, right?

Answer 6

yes

Answer 7

Part A
\[B = 703 \times \frac{w}{h^2}\]
multiply both sides by \(h^2\)
\[Bh^2=703w \]
divide both sides by 703
\[w=\frac{Bh^2}{703} \]

Answer 8

The 703 is given or you put it?

Answer 9

It is given as a 2 part question. I will write it how it looks ......

Question 16: "The formula to compute a person's body mass index is \[B = 703 * \left(\begin{matrix}w \\ h ^{2}\end{matrix}\right)\] B represents the body mass index. W is the person's weight in pounds, and h represents the person's height in inches.

Part A: "Solve for W" (which you already helped me understand)

Part B: "What is the weight (to the nearest pound) of a person who is 64 inches tall and has a body mass index of 21.45?"

Answer 10

For part B
\[B=703 \times \frac{w}{h^2}\]
multiply both sides by h^2
\[Bh^2=703w\]
divide both sides by 703
\[w=\frac{Bh^2}{703}\]
--------------------------------------------
B=21.45 , h= 64
\[w=\frac{(21.45)(64)^2}{703}\]

Answer 11

w=125

Answer 12

I'll be back in 2 hours, the answer for part B is my previous post

Answer 13

Thank you so much. I just figured it out with the calculator. By writing it down by hand step by step how you showed me. I now can understand it. Thanks. Are you available to check my work on another problem?