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Chemistry 12 Online
OpenStudy (anonymous):

What is the balanced equation for a reaction between potassium iodide and lead II chloride?

OpenStudy (anonymous):

OMG SO EASY MAN

OpenStudy (anonymous):

potassium iodide = \[KI\] lead (II) chloride = \[PbCl\] \[2 KI + PbCl _{2} -> 2 KCl + PbI _{2}\]

OpenStudy (anonymous):

ya what he said don't forget to balance yo

OpenStudy (anonymous):

2 KI + PbCl2 = 2 KCl + PbI2

OpenStudy (anonymous):

wanna be fiends tajj

OpenStudy (anonymous):

omg say yes please

OpenStudy (anonymous):

anadadstra

OpenStudy (anonymous):

why is BaOH aqueous :(

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