If you stand on a platform 230m above ground and throw something up at 30m/s. How many seconds elapse between the time you throw it and the moment it reaches the ground?

Question

anonymous · Answer

7.66666667

anonymous · Answer

Think about it.. can't you divide 230/30?

anonymous · Answer

No, this is not a time distance question. Requires the use of antiderivatives

anonymous · Answer

oh, sorry then! Can't help you on that yet! :P

anonymous · Answer

http://www.sparknotes.com/math/calcab/introductiontointegrals/section1.html

anonymous · Answer

This might help you; I use SparkNotes a LOT, and it usually helps every time. Good luck with your studies!

anonymous · Answer

Haha thanks rokotherodent

anonymous · Answer

whatcha need?

anonymous · Answer

start with acceleration

anonymous · Answer

v(0)=32

anonymous · Answer

you know acceleration due to gravity so you want to use that

anonymous · Answer

What is acceleration due to gravity?

anonymous · Answer

youw ant to do it in feet or m/s?

anonymous · Answer

-32 ft/sec is acceleration   i believe

anonymous · Answer

m/s please

anonymous · Answer

so gravity is 9.8m/s^2 corect

anonymous · Answer

however gravity is acting upon your ball on a negative aspect so your acceleration will be

a(t)=-9.8

anonymous · Answer

integrating this will get you v(t), correct?

anonymous · Answer

yes

anonymous · Answer

so when integrating what do you get

anonymous · Answer

why would you integrate this?

anonymous · Answer

you understand how integration and derivatives worth in the sense of velocity ,acceleration and position right?

anonymous · Answer

yes

anonymous · Answer

|dw:1338343932232:dw|