Question

a^2 + 5a + 4 / a^3 * a^2 + 3a + 2 / a^2 - 2a

Answer 1

oh ok, thx for clarifying

Answer 2

np

Answer 3

So the entire problem is \[\Large \left(\frac{a^2 + 5a + 4}{a^3} \right )\left(\frac{a^2 + 3a + 2}{a^2 - 2a} \right )\] correct?

Answer 4

yes

Answer 5

The first step is to factor a^2 + 5a + 4


a^2 + 5a + 4

a^2 + 4a + a + 4

(a^2+4a)+(a+4)

a(a+4)+1(a+4)

(a+1)(a+4)


So a^2 + 5a + 4 factors to (a+1)(a+4)

Answer 6

What do you get when you factor a^2 + 3a + 2 ??

Answer 7

umm idk

Answer 8

a^2 + 3a + 2

a^2 + 2a + a + 2

(a^2 + 2a) + (a + 2)

a(a+2)+1(a+2)

(a+1)(a+2)


So a^2 + 3a + 2 factors to (a+1)(a+2)

Answer 9

Then factor a^2 - 2a to get a(a-2)

Answer 10

so the answer is a+4/a+2?

Answer 11

Not quite

Answer 12

wait a second, are we dividing these two big fractions or multiplying them?

Answer 13

multiplying

Answer 14

alright, one sec

Answer 15

ok