Ask your own question, for FREE!
Mathematics 7 Online
OpenStudy (anonymous):

sqrt5^8n=125^(n+4)

OpenStudy (anonymous):

the 8n is not under the sqrt

Parth (parthkohli):

\(\Large \color{Black}{\Rightarrow(5^{1 \over 2})^{8n} = (5^3)^{n + 4} }\) Multiply the exponents and then just equate the exponents.

OpenStudy (lgbasallote):

\[\large 5^{\frac{1}{2}(8n)} = 5^{3(n+4)}\]

OpenStudy (cwtan):

Comparing the powers

OpenStudy (callisto):

\[\sqrt5^{8n}=125^{n+4}\]\[(5^{\frac{1}{2}})^{8n}=(5^3)^{n+4}\]4n = 3(n+4) Can you solve it here?

OpenStudy (lgbasallote):

\[\large 5^{4n} = 5^{3n + 12}\]

OpenStudy (anonymous):

there is no 1/2

OpenStudy (cwtan):

sqrt is power 1/2

OpenStudy (lgbasallote):

\[\sqrt 5 = 5^{\frac{1}{2}}\]

Parth (parthkohli):

\(\Large \color{Black}{\Rightarrow \sqrt[x]{y} = y^{1 \over x} }\)

OpenStudy (cwtan):

Why @ParthKohli equation seem bigger? lol

OpenStudy (lgbasallote):

got it @zackwashere ?

Parth (parthkohli):

@cwtan latex latex latex

OpenStudy (lgbasallote):

\[\LARGE \text{like this??}\]

OpenStudy (anonymous):

nono i'm confused

OpenStudy (cwtan):

wow pro latex

OpenStudy (lgbasallote):

where @zackwashere ?

OpenStudy (anonymous):

this is what it tells me to do....

Parth (parthkohli):

\(\huge \color{orange}{\text{HUGE!}}\)

OpenStudy (anonymous):

Which of the following is the solution to the equation

Parth (parthkohli):

4n = 3n + 12 Solve now!

OpenStudy (anonymous):

n = 12 n = 4 n = -4 n = -12 are the answers

OpenStudy (cwtan):

solve the equation and you will get the answer 4n=3n+12

Parth (parthkohli):

Subtract 3n from both sides to isolate n.

OpenStudy (anonymous):

12 is the answer?

Parth (parthkohli):

Yes!

OpenStudy (cwtan):

Believe urself~

OpenStudy (anonymous):

thank you.

Parth (parthkohli):

Lol yw

OpenStudy (cwtan):

Sometime Math need courage to accept the answer made by u own

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!