Question

2NaN3 yields----> 3N2 + 2Na

What volume of N2 gas measured at 1.3atm and 87C, would be produced by the reaction of 70g of NaN3?

Answer 1

ok first you need to calculate amount of nitrogen gas in moles that can be created from 70 g of NaN3, firs calculate amount of NaN3 in moles then look at the ratio like this:
n(NaN3) = m(NaN3)/M(NaN3)
n(N2)/n(NaN3)= 3/2
n(N2)= 3/2 * m(NaN3)/M(NaN3)
and then you just put it in pV=nRT (watch on units, they must be in kelvins and pascals)
you should get that volume is 0,03635 m3 or 36,35 dm3