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Mathematics 19 Online
OpenStudy (anonymous):

Simplify...... -14x^3/x^3-5x^4

OpenStudy (anonymous):

OpenStudy (callisto):

What is the common factor of the terms in the denominator?

OpenStudy (anonymous):

x^3?

OpenStudy (callisto):

Yes, take that out and group the other terms what do you get?

OpenStudy (anonymous):

-14/-5x^4

OpenStudy (callisto):

Not really... \[\frac{-14x^3}{x^3-5x^4}=\frac{-14x^3}{x^3(1-5x)}\] Got it?

OpenStudy (anonymous):

Ohhh! I see... The whole "factoring part" always confuses me.. So then the answer should be -14/1-5x? What about x? Shouldn't there be a "Where x cannot = something?

OpenStudy (callisto):

It is... the denominator of a fraction cannot be 0, so, put 1-5x=0 and solve x. You'll find what you want :)

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