Question

2.Calculate the molarity of the hydrochloric acid. the previouse answer stated there was a pH of 0.70 of HCl

Answer 1

pH=-log[H+] --> 0.70=-log[H+] --> -0.70=log[H+] --> 10^-.70=[H+]
0.20=[H+]
Since HCl is a strong acid, it completely dissociates into H+ and Cl- ions, so [H+] is the same as the molarity of the HCl. Therefore, the answer is 0.20 molar.

Answer 2

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