Question

Please solve this limit. Its answer is "1".

Answer 1

please give some steps:)

Answer 2

first calculate lim x->0 x^x

Answer 3

I don't know. please tell

Answer 4

put x= e^lnx
\[ \lim_{x->0}x^x = e^{\lim_{x->0} x \ln x }\]

calculate this \lim_{x->0} x \ln x

Answer 5

will we get 1.

Answer 6

you can place limit in the power of x^x^(put limit here)x^x ... you will get x^x^1 ... take limit again you will get 1

Answer 7

alternatively you can try substitution x^x = y
lim y->1 y^y

Answer 8

k! thanx a lot! I got it now 200%.

Answer 9

you made me do the same thing twice