Question

h(x) = x^2-6x
Put that function into the form (x-p)^2-q where p and q are constants

Answer 1

i got for p =3 and q = 9

Answer 2

\[(x-3)^2=x^2-6x+9\]
\[(x^2-3)^2- 9)

Answer 3

p = 3 and q = 9

Answer 4

is the inverse of that square root (x+9) +3

Answer 5

(x−3)2=x2−6x+9
compating
\[(x^2-3)^2- 9)\]
p=3
q=9

ps: q=9 cause \[(x-3)^2=x^2-6x+9\] and we wish \[x^2-6x=0\]