Question

can someone help me with mole ratios

Answer 1

give an example of what you mean...

Answer 2

ill repost it here so it would be easier:
determine the mass of sodium carbonate required to produce 23.4g of sodium chloride when it reacts with excess hydrochloric acid

Answer 3

ok so reaction is as it follows:
Na2CO3 + 2HCl -> 2NaCl + CO2 + H2O
now you have been given amount of NaCl needed to be produced so first step would be to calculate how many moles is needed to be produced
n= m/M = 23,4 g / 58,45 g mol-1 = 0,4 mole
so now we come to your question of mole ratios.
mole ratios are ratios in which substances are related so that by chemical reaction whole molecules react and give product.
in your case ratio between NaCl and Na2CO3 is 2:1 which means that it is needed for one molecule of Na2CO3 to react with 2 molecules of HCl to give 2 molecules of NaCl now put in equation:
n(Na2CO3)/n(NaCl) = 1/2 -->
n(Na2CO3) = 1/2 * n(NaCl) = 0,2 moles
so mass of reactant (Na2CO3) is:
m(Na2CO3)= n(Na2CO3) * M(Na2CO3) = 0,2 mol * 106 g mol-1 = 21,2 g
if you dont understand any step please say so we can clear it out...