Question

Someone please help! :)
(x^2-4)/(x-8)/(x-2)

(x^2+2x+1)/(x-2) over (x^2-1)/(x^2-4)

Answer 1

factor your terms first

Answer 2

So (x+2)(x-2)(x-2)/x-8; etc

Answer 3

Wait what?? haha

Answer 4

1st part isit
\[\frac{(x^2-4)}{\frac{x-8}{(x-2}}\]?

Answer 5

yes

Answer 6

or
\[\frac{(\frac{x^2-4}{x-8})}{x-2}\]
it has their difference

Answer 7

the first one

Answer 8

so @treeman5823 has gave u the answer.....

Let say
0.5=1/2

\[\frac{2}{\frac{1}{2}}\]
2/0.5=4 right?
That how we move
we move the 2 in the 1/2 to the numerator
that's it

Answer 9

ohh ok