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Mathematics 8 Online
OpenStudy (anonymous):

1 1 tan x ______ - ______ = 2 _____ 1-sin x 1+sin x cos x

OpenStudy (cwrw238):

you want to verify this identity?

OpenStudy (anonymous):

yes ..or 'prove' it if thats what you mean

OpenStudy (cwrw238):

yup

OpenStudy (cwrw238):

LHS = 1+ sinx - (1 - sinx) 2 sin x ---------------- = ------- 1 - sin^2 x 1 - sin^2 x now if you use the identities sin^x + cos^2x = 1 and tan x = sin x / cos x you can get the RHS

OpenStudy (anonymous):

the way we gotta do it in class is pick one side and make it look like the other, we cant change both

OpenStudy (anonymous):

i got up to 1 + sin x - (1 - sin x) -------------------- cos ^2 x

OpenStudy (anonymous):

but i dont know what to do next...

OpenStudy (cwrw238):

next simplify the numerator

OpenStudy (anonymous):

how?

OpenStudy (cwrw238):

well its just simple algebra - remove brackets to get 1 + sin x - 1 + sin x what does that give?

OpenStudy (cwrw238):

the 1's are eliminated right?

OpenStudy (anonymous):

2sin x?

OpenStudy (cwrw238):

yes

OpenStudy (cwrw238):

so you have 2 sin x ----- cos^2 x now sinx / cos x = tan x so .....

OpenStudy (anonymous):

divide one sin from the numerator with one cos from the denominator to get |dw:1338425726215:dw|

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