1 1 tan x
______ - ______ = 2 _____
1-sin x 1+sin x cos x
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OpenStudy (cwrw238):
you want to verify this identity?
OpenStudy (anonymous):
yes ..or 'prove' it if thats what you mean
OpenStudy (cwrw238):
yup
OpenStudy (cwrw238):
LHS = 1+ sinx - (1 - sinx) 2 sin x
---------------- = -------
1 - sin^2 x 1 - sin^2 x
now if you use the identities sin^x + cos^2x = 1
and tan x = sin x / cos x
you can get the RHS
OpenStudy (anonymous):
the way we gotta do it in class is pick one side and make it look like the other, we cant change both
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OpenStudy (anonymous):
i got up to 1 + sin x - (1 - sin x)
--------------------
cos ^2 x
OpenStudy (anonymous):
but i dont know what to do next...
OpenStudy (cwrw238):
next simplify the numerator
OpenStudy (anonymous):
how?
OpenStudy (cwrw238):
well its just simple algebra - remove brackets to get 1 + sin x - 1 + sin x
what does that give?
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OpenStudy (cwrw238):
the 1's are eliminated right?
OpenStudy (anonymous):
2sin x?
OpenStudy (cwrw238):
yes
OpenStudy (cwrw238):
so you have 2 sin x
-----
cos^2 x
now sinx / cos x = tan x so .....
OpenStudy (anonymous):
divide one sin from the numerator with one cos from the denominator to get |dw:1338425726215:dw|