Question

what is the answer to this?...PLZ Help!

Answer 1

you need to get a common denominator, do you know how to do that?

Answer 2

\[\frac{4}{m+2}+\frac{2}{m-2}\]
First make denominator same
\[(\frac{4}{m+2}\times\frac{m-2}{m-2})+(\frac{2}{m-2}\times \frac{m+2}{m+2})\]
\[\frac{4(m-2)}{(m+2)(m-2)}+\frac{2(m+2)}{(m-2)(m+2)}\]
The denominator is same , and you can combine it
\[\frac{4(m-2)+2(m+2)}{(m+2)(m-2)}\]
Try to simplify from here

Answer 3

Thanks.