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Chemistry 19 Online
OpenStudy (anonymous):

Pick the compound with a higher percent ionic character than KCl. -MgF -SrCl -NaF

OpenStudy (anonymous):

just substract electronegativities and one with higher difference is your choice

OpenStudy (anonymous):

I did not get that, how can I subtract the electronegatives and stuff?

OpenStudy (anonymous):

well take periodic table of elements and for example of KCl you have: electronegativity of: Cl -> 3,2 K -> 0,8 so substracted is 3,2-0,8 = 2,4 do you get it now?

OpenStudy (anonymous):

right, Krten just substract

OpenStudy (anonymous):

yes, alright, got it, thank you

OpenStudy (anonymous):

not a problem, glad to help

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