Question

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Answer 1

plug in for y

2x+2=x^2+3x-4

subtract 2x+2 from both sides

0=x^2+x-6

Answer 2

u got from there?

Answer 3

Basically use substitution. Since y is solved in the linear equation, plug it in for y.
2x + 2 = x^2 + 3x - 4
x^2 + x - 6 = 0
(x + 3)(x - 2) = 0
x = -3 or 2

Answer 4

@Calcmathlete I dont understand?

Answer 5

@cherrycool do u know FOIL?

Answer 6

You see, y is already solved for in y = 2x + 2. That same value of y is also in y= x^2 + 3x - 4. Since it's the same value, you can put 2x + 2 in for y in the quadratic equation.
2x + 2 = x^2 + 3x - 4
THen, like a quadratic, you set it equal to 0 by adding or subtracting the terms to the other side.
2x + 2 = x^2 + 3x - 4
- 2x + 2x + 2 = x^2 + 3x - 4 - 2x
- 2 - 2x + 2x + 2 = x^2 + 3x - 4 - 2x - 2
0 = x^2 + x - 6.
Now just solve for x.

Answer 7

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