Question

Rewrite the function in the form y = ( x − h ) 2 + k, and find the vertex: y = x2 − 12x

A. y = (x + 6 ) 2 − 36, vertex = ( 2, −6 )
B. y = ( x − 6 ) 2 + 36, vertex = ( 6, 0 )
C. y = ( x − 6 ) 2 − 36, vertex = ( 6, −36 )
D. y = x 2 − 36, vertex = ( −6, −6 )

Answer 1

Do you know how to complete the square?

Answer 2

@jordanguruu ?

Answer 3

no

Answer 4

satellite = jordanguruu?

Answer 5

no

Answer 6

i only know how to compute
\(-\frac{b}{2a}=-\frac{-12}{2}=6\) so vertex is \((6,-36)\) and it looks like \(y=(x+6)^2-36\)

Answer 7

In any quadratic equation, you must add (\({b \over 2})^2\) to both sides.

Answer 8

i still do not understand

Answer 9

can you help me?

Answer 10

yes... but the answer is already given.... do you need furthur explanation?

Answer 11

i dont see the answer

Answer 12

lemme check...

Answer 13

yes... you are correct...

Answer 14

ok..
the x coordinate of the vertex of any parabola \[\large y=ax^2+bx+c\]
is obtained by -b/(2a) where a , b, and c are the coefficients of the quadratic equation.

Answer 15

still with me?

Answer 16

i think so so the answer would be C?

A. y = (x + 6 ) 2 − 36, vertex = ( 2, −6 )

C. y = ( x − 6 ) 2 − 36, vertex = ( 6, −36 )

Answer 17

correct... C... :)

Answer 18

Yes!

Answer 19

A. doesn't have the vertex written correctly

Answer 20

ok

Answer 21

good work man... :)

Answer 22

i have one more question can you help me?

Answer 23

post it up as a new question...

Answer 24

Use the quadratic formula to solve the equation: 6x 2 − 5x + 1 = 0

A. x = 1 or x = – 1⁄2
B. x = 2 or x = −1
C. x = – 1 ⁄ 3 or x = 3
D. x = 1 ⁄ 2 or x = 1 ⁄ 3

Answer 25

can you help?