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Find the probability of drawing a pink card, not replacing it, and then drawing another pink card.
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\(\Large \color{Black}{\Rightarrow {4 \over 10} \times {3 \over 9} }\)
Because when we don't replace it we have a card less.
And that's why I've reduced one in the denominator.
\(\Large \color{Black}{\Rightarrow {2 \over 5} \times {1 \over 3} = {2 \over 15} }\)
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there are 10 cards...4 pink cards...the first probability will be 4/10 the second probability will be 3/9 because there will only be 3 pink cards left (since one of the cards has already been drawn) and 9 because one of the cards has already been drawn
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