Question

solve by using the quadratic formula
5x^2+2x=3

Answer 1

first we must put all terms on the left side so itbecomes \(5x^2 + 2x - 3 = 0\)

now we can use the quadratic formula...

quadratic formula is \[x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\] so if we substitute... \[x = \frac{-2 \pm \sqrt{2^2 - 4(5)(-3)}}{2(5)}\] \[x = \frac{ -2 \pm \sqrt{4 +60}}{10}\] \[x = \frac{ -2 \pm \sqrt{64}}{10}\]

Answer 2

\[x = \frac{-2 \pm 8}{10}\]

Answer 3

can you do the rest?

Answer 4

\(x = \frac{-2 \pm 8}{10}\) means that \(x = \frac{-2 + 8}{10}\) and \(x = \frac{-2 - 8}{10}\)

therefore when \(x = \frac{-2 + 8}{10}\) the answer is \(x = \frac{-6}{10} = -\frac{3}{5}\)

when \(x = \frac{-2 - 8}{10}\) the answer becomes \(x = \frac{-10}{10} = -1\)

Answer 5

Thank you.