find the following limits analytically: f(x)= {x-3, x can't = 1} and {0, x=1} lim x-1 f(x) =

Question

find the following limits analytically: f(x)= {x-3, x can't = 1} and {0, x=1} lim x->1 f(x) =

anonymous · Answer

what does "analytically" mean?

anonymous · Answer

the limit is $1-3=-2$ because the limit does not depend on the actual value of the function at $x=1$ but only on what the function approaches. since you have $f(x)=x-3$ for all $x$ except $x=1$ the limit is -2

anonymous · Answer

thanks! how do i figure out the second one?

anonymous · Answer

what second one? i thought this was one question, not two

anonymous · Answer

its in brackets and is one big question it is x-3, x can't= 1
                                                              0,     x=1              all in brackets

anonymous · Answer

yes it is a piecewise function and you are asked for the limit as x goes to 1
answer is -2

anonymous · Answer

oh ok thanks!

anonymous · Answer

i have a few more questions to ask if that is ok