Question

312 mL of 1.50 x 10^-2 M NaOH is used to titrate 225 mL of a monoprotic acid of unknown concentration to reach the equivalence point. What is the molarity of the acid?


1.50 x 10^-2 M

4.68 x 10^-3 M

2.08 x 10^-2 M

1.05 x 10^-3 M

Answer 1

ok so you probably know this equation:
c=n/V -> n=c*V
using this equation you should calculate amount of NaOH in moles
then you know from the text that it is monoprotonic acid so ratio of NaOH: X = 1:1
now that we know that we know that amount of X is equal to amount of NaOH so now we just calculate its concentration by dividing moles with its volume.

Answer 2

and the answer is:
2.08 x 10^-2 M

Answer 3

he he, you should open new question but you can look one question under yours, its the same question :)
you are obviously solving same test :)

Answer 4

oh lol that is really weird. there is a lot of my classmates that come here

Answer 5

:)