A model rocket is launched from a roof into a large field. The path of the rocket can be modeled by the equation y = 0.04x+ 8.3x + 4.3, where x is the horizontal distance, in meters, from the starting point on the roof and y is the height, in meters, of the rocket above the ground. How far horizontally from its starting point will the rocket land?

-8.3 +- √((8.3^2) - (4)(0.04)(4.3)) / (2)(0.04)
-8.3 +- √68.202 / 0.08
-8.3 + √68.202 / 0.08
-0.519372
= -0.52

Is my equation right??

Question

A model rocket is launched from a roof into a large field. The path of the rocket can be modeled by the equation y = 0.04x+ 8.3x + 4.3, where x is the horizontal distance, in meters, from the starting point on the roof and y is the height, in meters, of the rocket above the ground. How far horizontally from its starting point will the rocket land?

-8.3 +- √((8.3^2) - (4)(0.04)(4.3)) / (2)(0.04)
-8.3 +- √68.202 / 0.08
-8.3 + √68.202 / 0.08
-0.519372
= -0.52

Is my equation right??

anonymous · Answer

some thing doesn't add up here the equation you stated is not quadratic unless you missed the square term. and I don't see a height dor the roof?

anonymous · Answer

Alright, I'm lost. This word problem is confusing me. It wants to know how far, in meters, across the field to the landing point the rocket landed?

anonymous · Answer

Are you sure there is nothing more to the question?

anonymous · Answer

I apologize. The equation should look like this: y = -0.04x^2+ 8.3x + 4.3

anonymous · Answer

ah! ok :D In that case it 208.017 meters provided we dont have to adjust for the height of the roof