Question

Balance the combustion reaction between octane and oxygen.
2C^8H^8+___O^2→____CO^2+___H^2O

Answer 1

@mapa_ramos This section is for maths questions, next time please post Chemistry Questions in Chemistry:)
Thanks
Nevertheless I'll help you here!!

Answer 2

\[2C_8H_8+O_2 \longrightarrow CO_2+H_2O\]
Tell me how many carbon atoms are on the left side?

Answer 3

I know, but in the chemistry Questions section nobody helps me...umm 2?

Answer 4

\[2C_8=> 2\times 8=16\], so I require 16 C on the right side also, I multiply 16 to C
\[2C_8H_8+O_2 \longrightarrow \overbrace {16}CO_2+H_2O\]
Do you get this?

Answer 5

yes, I did get that

Answer 6

Now tell me the no. of Hydrogen on left and right side?

Answer 7

So hydrogen would be 2*9=18 so on the other side it would be 9H^2?

Answer 8

It's 2*8 on the left side

Answer 9

yeah, but on the other side left side second space..ok I`m lost again

Answer 10

16 on the left side, right side we have 2, so we multiply by 8 (16=8*2)
\[2C_8H_8+O_2 \longrightarrow {16}CO_2+\overbrace{8}H_2O\]

Answer 11

Now you find the no. of Oxygen on the left side and right side?

Answer 12

so there is O^2 on the left side and O o the right side?

Answer 13

*on

Answer 14

\[2C_8H_8+O_2 \longrightarrow {16}CO_2+{8}H_2O\]
2 O on left and (16*2+8=40) on the right
so what should we multiply left side \(O_2\) with??

Answer 15

20?

Answer 16

Yeah you're right, so our balanced equation is
\[ \huge\color {gold }{ {2C_8H_8+20O_2 \longrightarrow {16}CO_2+8H_2O}}\]

Answer 17

okay I got everything except to the 8H^2O, how did you get that one since the other side is just H^2?

Answer 18

Left side
\[2 \times 8=16\]
Right side
we have \(H_2\) so 2
we need 16 both sides
so I multiply 8

Answer 19

ohh okay, thank you very much :)

Answer 20

did you understand?

Answer 21

yes :)