How do I set this p? Use the compound interest formula to compute the total amount accumulated. $10,000 for 20 years at 5% compounded annually. A. $20,000.00 B. $25,269.50 C. $19,500.00 D. $26,532.98
post the formula
A=P(1+r/n)^(nt)
\[ P= P_0\left( 1 + r) \right)^n \]
r as a decimal rather than a percentage, n as the number of compoundings per year, and t as the time in years.
\[ 10000(1.05)^{20} \]
Looks right
. $26,532.98
10,000 *(1+.05)^(20) D
that s 2 diferent formulas you guys are givin me. so witch one is it?
Yep. That looks right. @LilRyG - They're both right
well the one with the n the n is just one. :)
Except n means something different in her formula.
n represents the number of years. Hers is only good for annual compounding.
A=P(1+r/n)^(nt) the n is used to manipulate it to yearly quarterly or monthly
with 1 it is yearly
with n=12 montly n=12/4 quarterly
okay thank you guys!!
de nada :)
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