How do I set this p?
Use the compound interest formula to compute the total amount accumulated. $10,000 for 20 years at 5% compounded annually.
A. $20,000.00 B. $25,269.50 C. $19,500.00 D. $26,532.98
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OpenStudy (anonymous):
post the formula
OpenStudy (anonymous):
A=P(1+r/n)^(nt)
OpenStudy (anonymous):
\[
P= P_0\left( 1 + r) \right)^n
\]
OpenStudy (anonymous):
r as a decimal rather than a percentage, n as the number of compoundings per year, and t as the time in years.
OpenStudy (anonymous):
\[
10000(1.05)^{20}
\]
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OpenStudy (anonymous):
Looks right
OpenStudy (anonymous):
. $26,532.98
OpenStudy (anonymous):
10,000 *(1+.05)^(20)
D
OpenStudy (anonymous):
that s 2 diferent formulas you guys are givin me. so witch one is it?
OpenStudy (anonymous):
Yep. That looks right.
@LilRyG - They're both right
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OpenStudy (anonymous):
well the one with the n the n is just one. :)
OpenStudy (anonymous):
Except n means something different in her formula.
OpenStudy (anonymous):
n represents the number of years. Hers is only good for annual compounding.
OpenStudy (anonymous):
A=P(1+r/n)^(nt) the n is used to manipulate it to yearly quarterly or monthly
OpenStudy (anonymous):
with 1 it is yearly
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