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OpenStudy (anonymous):
get aeay
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OpenStudy (anonymous):
first write the oxidation states of every element above and then you can see what is being reduced and what oxidised
OpenStudy (anonymous):
SbH3
OpenStudy (anonymous):
nope MnO4-, SbH3 is oxidized Sb is -3 and on product side it is 0
OpenStudy (anonymous):
What is the reducing agent in the reaction?
OpenStudy (anonymous):
chemical that is being reduced is oxidising agent and vice versa
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OpenStudy (anonymous):
so its MN04-
OpenStudy (anonymous):
no MnO4- is being reduced so it is oxidising agent and SbH3 is being oxidised so it is reducing agent
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