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Chemistry 17 Online
OpenStudy (anonymous):

get aeay

OpenStudy (anonymous):

first write the oxidation states of every element above and then you can see what is being reduced and what oxidised

OpenStudy (anonymous):

SbH3

OpenStudy (anonymous):

nope MnO4-, SbH3 is oxidized Sb is -3 and on product side it is 0

OpenStudy (anonymous):

What is the reducing agent in the reaction?

OpenStudy (anonymous):

chemical that is being reduced is oxidising agent and vice versa

OpenStudy (anonymous):

so its MN04-

OpenStudy (anonymous):

no MnO4- is being reduced so it is oxidising agent and SbH3 is being oxidised so it is reducing agent

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