Question

Choose the correct simplification of (4a^4b^2)^2.
Answer
16a^6b^4
8a^6b^4
16a^8b^4
8a^8b^4

Answer 1

@AccessDenied

Answer 2

I'm confused on what numbers i multiply

Answer 3

Here, we use these properties
\( \large (mn)^x = m^x n^x\):
\(\large (x^a)^b = x^{a\times b} \)

First we bring the power outside to each factor, and then the second property for our variables.

Answer 4

k

Answer 5

then what?

Answer 6

Simplify, and that should be it!
The first step looks like this:
\( \large (4a^4 b^2)^2 = 4^2 (a^4)^2 (b^2)^2 \)
Kind of like an 'exponent-distributive property'.

Answer 7

The second property then lets us take those 'powers to a power' into one exponent:
= 16 a^(4*2) b^(2*2)
From here, we just simplify the multiplication: 4*2 = 8, 2*2 = 4...

Answer 8

so last option?

Answer 9

hey why does it say theres someone else viewing this but wont let me see their profile o_O

Answer 10

its kind of like a facebook picture b4 u put ur own up...

Answer 11

4^2 = 4*4 = 16, so it can't be the last one with an 8 coefficient.

It's a guest who hasn't registered. Hopefully they consider it. :P

Answer 12

ahh ok

Answer 13

first option?

Answer 14

Close... except I think you're confusing the multiplication of exponents with addition of exponents....
= 16 a^([[4*2]]) b^([[2*2]]) 4*2 = 8, 2*2 = 4; we can directly insert that back in:
=16 a^8 b^4

Answer 15

alright thanks