Question

x2+6x-8=0 soleve by completeing the square !
please help im doing it on the exam and i dont know this one
!

Answer 1

thnks for helping!

Answer 2

you need to find the value of (6/2)^2

rewrite the equation

\[x^2 + 6x = 8\]

then add (6/2)^2 to both sides

\[x^2 + 6x + 9 = 8 + 9\]

which can be factorised

\[(x +3)^2 = 17\]

now solve for x

\[x + 3 = \pm \sqrt{17}\]

then

\[x = - 3 \pm \sqrt{17}\]

Answer 3

so x=-3+-sqr root 17
?

Answer 4

thats the answer?

Answer 5

yes... hope it helps

Answer 6

thank youu!!!!